Independent random variables - Exercise set 1

This exercise set contains some solved exercises on independent random variables. The theory needed to solve these exercises is introduced in the lecture entitled Independent random variables.

Exercise 1.1

Consider two random variables X and Y having marginal distribution functions[eq1]If X and Y are independent, what is their joint distribution function?

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For X and Y to be independent, their joint distribution function must be equal to the product of their marginal distribution functions:[eq2]

Exercise 1.2

Let [eq3] be a discrete random vector with support: [eq4]Let its joint probability mass function be:[eq5]Are X and Y independent?

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In order to verify whether X and Y are independent, we first need to derive the marginal probability mass functions of X and Y. The support of X is:[eq6]and the support of Y is:[eq7]We need to compute the probability of each element of the support of X:[eq8]Thus, the probability mass function of X is:[eq9]We need to compute the probability of each element of the support of Y:[eq10]Thus, the probability mass function of Y is:[eq11]The product of the marginal probability mass functions is:[eq12]which is equal to [eq13]. Therefore, X and Y are independent.

Exercise 1.3

Let [eq14] be an absolutely continuous random vector with support: [eq15]and its joint probability density function be:[eq16]Are X and Y independent?

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The support of Y is:[eq17]When [eq18], the marginal probability density function of Y is 0, while, when [eq19], the marginal probability density function of Y is:[eq20]Thus, summing up, the marginal probability density function of Y is:[eq21]The support of X is:[eq22]When [eq23], the marginal probability density function of X is 0, while, when [eq24], the marginal probability density function of X is:[eq25]Thus, the marginal probability density function of X is:[eq26]Verifying that [eq27] is straightforward. When [eq23] or [eq29], then [eq30]. When [eq31] and [eq32], then:[eq33]Thus, X and Y are independent.

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