Chebyshev's inequality

Let X be a random variable having finite mean mu and finite variance sigma^2. Let k be a strictly positive constant. Then, the following inequality, called Chebyshev's inequality, holds:[formula]

Thus, Chebyshev's inequality gives an upper bound to the probability that the absolute deviation of X from its mean exceeds a certain threshold k.

More details about Chebyshev's inequality can be found in the lecture entitled Basic probabilistic inequalities.

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